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The integral of cos (lnx) is an antiderivative of cos (ln x) function which is equal to ½ [xsin (ln x) + xcos (ln x)]. It is also known as the reverse derivative of sine function which is a trigonometric identity. The sine function is the ratio of adjacent side to the hypotenuse of a triangle which is written as: cos = adjacent side / hypotenuse


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Example 3.5.2: Finding the Derivative of a Function Containing cos x. Find the derivative of g(x) = cosx 4x2. Solution. By applying the quotient rule, we have. g′ (x) = ( − sinx)4x2 − 8x(cosx) (4x2)2. Simplifying, we obtain. g′ (x) = − 4x2sinx − 8xcosx 16x4 = − xsinx − 2cosx 4x3.


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so basically the derivative of a function has the same domain as the function itself. Therefore the derivative of the function f (x)= ln (x), which is defined only of x > 0, is also defined only for x > 0 (f' (x) = 1/x where x > 0). i hope this makes sense. ( 2 votes)


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Cos(ln x) dx = 11_(a) sin (In x) + c(b) COS (In x) + … SolvedLib

1 Answer Jim H Aug 30, 2015 Integrate by parts (twice). Explanation: Looking at ∫cos(lnx)dx, we realize that if can't integrate straight away. Next thought is, perhaps we could use substitution. We would need cos(lnx) 1 x to integrate by substitution.


Let f(x)=\cos (\ln x) (a) Find the absolute extreme… SolvedLib

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Figure 6.2.7: Setting up Integration by Parts. Putting this all together in the Integration by Parts formula, things work out very nicely: $$\int \ln x\,dx = x\ln x - \int x\,\frac1x\,dx.\] The new integral simplifies to ∫ 1dx, which is about as simple as things get. Its integral is x + C and our answer is.